Optimal. Leaf size=291 \[ -a^3 x+\frac {15}{2} a b^2 x-\frac {45 a^2 b \tanh ^{-1}(\cos (c+d x))}{8 d}+\frac {5 b^3 \tanh ^{-1}(\cos (c+d x))}{2 d}+\frac {45 a^2 b \cos (c+d x)}{8 d}-\frac {5 b^3 \cos (c+d x)}{2 d}-\frac {5 b^3 \cos ^3(c+d x)}{6 d}-\frac {a^3 \cot (c+d x)}{d}+\frac {15 a b^2 \cot (c+d x)}{2 d}+\frac {15 a^2 b \cos (c+d x) \cot ^2(c+d x)}{8 d}-\frac {b^3 \cos ^3(c+d x) \cot ^2(c+d x)}{2 d}+\frac {a^3 \cot ^3(c+d x)}{3 d}-\frac {5 a b^2 \cot ^3(c+d x)}{2 d}+\frac {3 a b^2 \cos ^2(c+d x) \cot ^3(c+d x)}{2 d}-\frac {3 a^2 b \cos (c+d x) \cot ^4(c+d x)}{4 d}-\frac {a^3 \cot ^5(c+d x)}{5 d} \]
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Rubi [A]
time = 0.17, antiderivative size = 291, normalized size of antiderivative = 1.00, number of steps
used = 21, number of rules used = 10, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.476, Rules used = {2801, 2672,
294, 308, 212, 2671, 209, 327, 3554, 8} \begin {gather*} -\frac {a^3 \cot ^5(c+d x)}{5 d}+\frac {a^3 \cot ^3(c+d x)}{3 d}-\frac {a^3 \cot (c+d x)}{d}-a^3 x+\frac {45 a^2 b \cos (c+d x)}{8 d}-\frac {3 a^2 b \cos (c+d x) \cot ^4(c+d x)}{4 d}+\frac {15 a^2 b \cos (c+d x) \cot ^2(c+d x)}{8 d}-\frac {45 a^2 b \tanh ^{-1}(\cos (c+d x))}{8 d}-\frac {5 a b^2 \cot ^3(c+d x)}{2 d}+\frac {15 a b^2 \cot (c+d x)}{2 d}+\frac {3 a b^2 \cos ^2(c+d x) \cot ^3(c+d x)}{2 d}+\frac {15}{2} a b^2 x-\frac {5 b^3 \cos ^3(c+d x)}{6 d}-\frac {5 b^3 \cos (c+d x)}{2 d}-\frac {b^3 \cos ^3(c+d x) \cot ^2(c+d x)}{2 d}+\frac {5 b^3 \tanh ^{-1}(\cos (c+d x))}{2 d} \end {gather*}
Antiderivative was successfully verified.
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Rule 8
Rule 209
Rule 212
Rule 294
Rule 308
Rule 327
Rule 2671
Rule 2672
Rule 2801
Rule 3554
Rubi steps
\begin {align*} \int \cot ^6(c+d x) (a+b \sin (c+d x))^3 \, dx &=\int \left (b^3 \cos ^3(c+d x) \cot ^3(c+d x)+3 a b^2 \cos ^2(c+d x) \cot ^4(c+d x)+3 a^2 b \cos (c+d x) \cot ^5(c+d x)+a^3 \cot ^6(c+d x)\right ) \, dx\\ &=a^3 \int \cot ^6(c+d x) \, dx+\left (3 a^2 b\right ) \int \cos (c+d x) \cot ^5(c+d x) \, dx+\left (3 a b^2\right ) \int \cos ^2(c+d x) \cot ^4(c+d x) \, dx+b^3 \int \cos ^3(c+d x) \cot ^3(c+d x) \, dx\\ &=-\frac {a^3 \cot ^5(c+d x)}{5 d}-a^3 \int \cot ^4(c+d x) \, dx-\frac {\left (3 a^2 b\right ) \text {Subst}\left (\int \frac {x^6}{\left (1-x^2\right )^3} \, dx,x,\cos (c+d x)\right )}{d}-\frac {\left (3 a b^2\right ) \text {Subst}\left (\int \frac {x^6}{\left (1+x^2\right )^2} \, dx,x,\cot (c+d x)\right )}{d}-\frac {b^3 \text {Subst}\left (\int \frac {x^6}{\left (1-x^2\right )^2} \, dx,x,\cos (c+d x)\right )}{d}\\ &=-\frac {b^3 \cos ^3(c+d x) \cot ^2(c+d x)}{2 d}+\frac {a^3 \cot ^3(c+d x)}{3 d}+\frac {3 a b^2 \cos ^2(c+d x) \cot ^3(c+d x)}{2 d}-\frac {3 a^2 b \cos (c+d x) \cot ^4(c+d x)}{4 d}-\frac {a^3 \cot ^5(c+d x)}{5 d}+a^3 \int \cot ^2(c+d x) \, dx+\frac {\left (15 a^2 b\right ) \text {Subst}\left (\int \frac {x^4}{\left (1-x^2\right )^2} \, dx,x,\cos (c+d x)\right )}{4 d}-\frac {\left (15 a b^2\right ) \text {Subst}\left (\int \frac {x^4}{1+x^2} \, dx,x,\cot (c+d x)\right )}{2 d}+\frac {\left (5 b^3\right ) \text {Subst}\left (\int \frac {x^4}{1-x^2} \, dx,x,\cos (c+d x)\right )}{2 d}\\ &=-\frac {a^3 \cot (c+d x)}{d}+\frac {15 a^2 b \cos (c+d x) \cot ^2(c+d x)}{8 d}-\frac {b^3 \cos ^3(c+d x) \cot ^2(c+d x)}{2 d}+\frac {a^3 \cot ^3(c+d x)}{3 d}+\frac {3 a b^2 \cos ^2(c+d x) \cot ^3(c+d x)}{2 d}-\frac {3 a^2 b \cos (c+d x) \cot ^4(c+d x)}{4 d}-\frac {a^3 \cot ^5(c+d x)}{5 d}-a^3 \int 1 \, dx-\frac {\left (45 a^2 b\right ) \text {Subst}\left (\int \frac {x^2}{1-x^2} \, dx,x,\cos (c+d x)\right )}{8 d}-\frac {\left (15 a b^2\right ) \text {Subst}\left (\int \left (-1+x^2+\frac {1}{1+x^2}\right ) \, dx,x,\cot (c+d x)\right )}{2 d}+\frac {\left (5 b^3\right ) \text {Subst}\left (\int \left (-1-x^2+\frac {1}{1-x^2}\right ) \, dx,x,\cos (c+d x)\right )}{2 d}\\ &=-a^3 x+\frac {45 a^2 b \cos (c+d x)}{8 d}-\frac {5 b^3 \cos (c+d x)}{2 d}-\frac {5 b^3 \cos ^3(c+d x)}{6 d}-\frac {a^3 \cot (c+d x)}{d}+\frac {15 a b^2 \cot (c+d x)}{2 d}+\frac {15 a^2 b \cos (c+d x) \cot ^2(c+d x)}{8 d}-\frac {b^3 \cos ^3(c+d x) \cot ^2(c+d x)}{2 d}+\frac {a^3 \cot ^3(c+d x)}{3 d}-\frac {5 a b^2 \cot ^3(c+d x)}{2 d}+\frac {3 a b^2 \cos ^2(c+d x) \cot ^3(c+d x)}{2 d}-\frac {3 a^2 b \cos (c+d x) \cot ^4(c+d x)}{4 d}-\frac {a^3 \cot ^5(c+d x)}{5 d}-\frac {\left (45 a^2 b\right ) \text {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\cos (c+d x)\right )}{8 d}-\frac {\left (15 a b^2\right ) \text {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\cot (c+d x)\right )}{2 d}+\frac {\left (5 b^3\right ) \text {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\cos (c+d x)\right )}{2 d}\\ &=-a^3 x+\frac {15}{2} a b^2 x-\frac {45 a^2 b \tanh ^{-1}(\cos (c+d x))}{8 d}+\frac {5 b^3 \tanh ^{-1}(\cos (c+d x))}{2 d}+\frac {45 a^2 b \cos (c+d x)}{8 d}-\frac {5 b^3 \cos (c+d x)}{2 d}-\frac {5 b^3 \cos ^3(c+d x)}{6 d}-\frac {a^3 \cot (c+d x)}{d}+\frac {15 a b^2 \cot (c+d x)}{2 d}+\frac {15 a^2 b \cos (c+d x) \cot ^2(c+d x)}{8 d}-\frac {b^3 \cos ^3(c+d x) \cot ^2(c+d x)}{2 d}+\frac {a^3 \cot ^3(c+d x)}{3 d}-\frac {5 a b^2 \cot ^3(c+d x)}{2 d}+\frac {3 a b^2 \cos ^2(c+d x) \cot ^3(c+d x)}{2 d}-\frac {3 a^2 b \cos (c+d x) \cot ^4(c+d x)}{4 d}-\frac {a^3 \cot ^5(c+d x)}{5 d}\\ \end {align*}
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Mathematica [A]
time = 1.73, size = 346, normalized size = 1.19 \begin {gather*} \frac {-600 a \left (2 a^2-15 b^2\right ) (c+d x) \csc ^4(c+d x)+1200 b \left (-9 a^2+4 b^2\right ) \left (\log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right )-\log \left (\sin \left (\frac {1}{2} (c+d x)\right )\right )\right )+5 \cot (c+d x) \csc ^4(c+d x) \left (-80 a^3+285 a b^2+12 b \left (60 a^2-29 b^2\right ) \sin (c+d x)\right )+\csc ^5(c+d x) \left (5 \left (40 a^3-489 a b^2\right ) \cos (3 (c+d x))+\left (-184 a^3+1065 a b^2\right ) \cos (5 (c+d x))+5 \left (-9 a b^2 \cos (7 (c+d x))+60 a \left (2 a^2-15 b^2\right ) (c+d x) \sin (3 (c+d x))-306 a^2 b \sin (4 (c+d x))+122 b^3 \sin (4 (c+d x))-24 a^3 c \sin (5 (c+d x))+180 a b^2 c \sin (5 (c+d x))-24 a^3 d x \sin (5 (c+d x))+180 a b^2 d x \sin (5 (c+d x))+36 a^2 b \sin (6 (c+d x))-22 b^3 \sin (6 (c+d x))-b^3 \sin (8 (c+d x))\right )\right )}{1920 d} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.29, size = 289, normalized size = 0.99
method | result | size |
derivativedivides | \(\frac {a^{3} \left (-\frac {\left (\cot ^{5}\left (d x +c \right )\right )}{5}+\frac {\left (\cot ^{3}\left (d x +c \right )\right )}{3}-\cot \left (d x +c \right )-d x -c \right )+3 a^{2} b \left (-\frac {\cos ^{7}\left (d x +c \right )}{4 \sin \left (d x +c \right )^{4}}+\frac {3 \left (\cos ^{7}\left (d x +c \right )\right )}{8 \sin \left (d x +c \right )^{2}}+\frac {3 \left (\cos ^{5}\left (d x +c \right )\right )}{8}+\frac {5 \left (\cos ^{3}\left (d x +c \right )\right )}{8}+\frac {15 \cos \left (d x +c \right )}{8}+\frac {15 \ln \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right )}{8}\right )+3 a \,b^{2} \left (-\frac {\cos ^{7}\left (d x +c \right )}{3 \sin \left (d x +c \right )^{3}}+\frac {4 \left (\cos ^{7}\left (d x +c \right )\right )}{3 \sin \left (d x +c \right )}+\frac {4 \left (\cos ^{5}\left (d x +c \right )+\frac {5 \left (\cos ^{3}\left (d x +c \right )\right )}{4}+\frac {15 \cos \left (d x +c \right )}{8}\right ) \sin \left (d x +c \right )}{3}+\frac {5 d x}{2}+\frac {5 c}{2}\right )+b^{3} \left (-\frac {\cos ^{7}\left (d x +c \right )}{2 \sin \left (d x +c \right )^{2}}-\frac {\left (\cos ^{5}\left (d x +c \right )\right )}{2}-\frac {5 \left (\cos ^{3}\left (d x +c \right )\right )}{6}-\frac {5 \cos \left (d x +c \right )}{2}-\frac {5 \ln \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right )}{2}\right )}{d}\) | \(289\) |
default | \(\frac {a^{3} \left (-\frac {\left (\cot ^{5}\left (d x +c \right )\right )}{5}+\frac {\left (\cot ^{3}\left (d x +c \right )\right )}{3}-\cot \left (d x +c \right )-d x -c \right )+3 a^{2} b \left (-\frac {\cos ^{7}\left (d x +c \right )}{4 \sin \left (d x +c \right )^{4}}+\frac {3 \left (\cos ^{7}\left (d x +c \right )\right )}{8 \sin \left (d x +c \right )^{2}}+\frac {3 \left (\cos ^{5}\left (d x +c \right )\right )}{8}+\frac {5 \left (\cos ^{3}\left (d x +c \right )\right )}{8}+\frac {15 \cos \left (d x +c \right )}{8}+\frac {15 \ln \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right )}{8}\right )+3 a \,b^{2} \left (-\frac {\cos ^{7}\left (d x +c \right )}{3 \sin \left (d x +c \right )^{3}}+\frac {4 \left (\cos ^{7}\left (d x +c \right )\right )}{3 \sin \left (d x +c \right )}+\frac {4 \left (\cos ^{5}\left (d x +c \right )+\frac {5 \left (\cos ^{3}\left (d x +c \right )\right )}{4}+\frac {15 \cos \left (d x +c \right )}{8}\right ) \sin \left (d x +c \right )}{3}+\frac {5 d x}{2}+\frac {5 c}{2}\right )+b^{3} \left (-\frac {\cos ^{7}\left (d x +c \right )}{2 \sin \left (d x +c \right )^{2}}-\frac {\left (\cos ^{5}\left (d x +c \right )\right )}{2}-\frac {5 \left (\cos ^{3}\left (d x +c \right )\right )}{6}-\frac {5 \cos \left (d x +c \right )}{2}-\frac {5 \ln \left (\csc \left (d x +c \right )-\cot \left (d x +c \right )\right )}{2}\right )}{d}\) | \(289\) |
risch | \(-a^{3} x +\frac {15 a \,b^{2} x}{2}-\frac {b^{3} {\mathrm e}^{3 i \left (d x +c \right )}}{24 d}-\frac {3 i a \,b^{2} {\mathrm e}^{2 i \left (d x +c \right )}}{8 d}+\frac {3 b \,{\mathrm e}^{i \left (d x +c \right )} a^{2}}{2 d}-\frac {9 b^{3} {\mathrm e}^{i \left (d x +c \right )}}{8 d}+\frac {3 b \,{\mathrm e}^{-i \left (d x +c \right )} a^{2}}{2 d}-\frac {9 b^{3} {\mathrm e}^{-i \left (d x +c \right )}}{8 d}+\frac {3 i a \,b^{2} {\mathrm e}^{-2 i \left (d x +c \right )}}{8 d}-\frac {b^{3} {\mathrm e}^{-3 i \left (d x +c \right )}}{24 d}+\frac {840 i a \,b^{2}-1120 i a^{3} {\mathrm e}^{4 i \left (d x +c \right )}-405 a^{2} b \,{\mathrm e}^{9 i \left (d x +c \right )}+60 b^{3} {\mathrm e}^{9 i \left (d x +c \right )}+4800 i a \,b^{2} {\mathrm e}^{4 i \left (d x +c \right )}-360 i a^{3} {\mathrm e}^{8 i \left (d x +c \right )}+450 a^{2} b \,{\mathrm e}^{7 i \left (d x +c \right )}-120 b^{3} {\mathrm e}^{7 i \left (d x +c \right )}-3600 i a \,b^{2} {\mathrm e}^{6 i \left (d x +c \right )}-3120 i a \,b^{2} {\mathrm e}^{2 i \left (d x +c \right )}-184 i a^{3}+560 i a^{3} {\mathrm e}^{2 i \left (d x +c \right )}-450 a^{2} b \,{\mathrm e}^{3 i \left (d x +c \right )}+120 b^{3} {\mathrm e}^{3 i \left (d x +c \right )}+1080 i a \,b^{2} {\mathrm e}^{8 i \left (d x +c \right )}+720 i a^{3} {\mathrm e}^{6 i \left (d x +c \right )}+405 a^{2} b \,{\mathrm e}^{i \left (d x +c \right )}-60 b^{3} {\mathrm e}^{i \left (d x +c \right )}}{60 d \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )^{5}}-\frac {45 a^{2} b \ln \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )}{8 d}+\frac {5 b^{3} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )}{2 d}+\frac {45 a^{2} b \ln \left ({\mathrm e}^{i \left (d x +c \right )}-1\right )}{8 d}-\frac {5 b^{3} \ln \left ({\mathrm e}^{i \left (d x +c \right )}-1\right )}{2 d}\) | \(511\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.66, size = 252, normalized size = 0.87 \begin {gather*} -\frac {16 \, {\left (15 \, d x + 15 \, c + \frac {15 \, \tan \left (d x + c\right )^{4} - 5 \, \tan \left (d x + c\right )^{2} + 3}{\tan \left (d x + c\right )^{5}}\right )} a^{3} - 120 \, {\left (15 \, d x + 15 \, c + \frac {15 \, \tan \left (d x + c\right )^{4} + 10 \, \tan \left (d x + c\right )^{2} - 2}{\tan \left (d x + c\right )^{5} + \tan \left (d x + c\right )^{3}}\right )} a b^{2} + 20 \, {\left (4 \, \cos \left (d x + c\right )^{3} - \frac {6 \, \cos \left (d x + c\right )}{\cos \left (d x + c\right )^{2} - 1} + 24 \, \cos \left (d x + c\right ) - 15 \, \log \left (\cos \left (d x + c\right ) + 1\right ) + 15 \, \log \left (\cos \left (d x + c\right ) - 1\right )\right )} b^{3} + 45 \, a^{2} b {\left (\frac {2 \, {\left (9 \, \cos \left (d x + c\right )^{3} - 7 \, \cos \left (d x + c\right )\right )}}{\cos \left (d x + c\right )^{4} - 2 \, \cos \left (d x + c\right )^{2} + 1} - 16 \, \cos \left (d x + c\right ) + 15 \, \log \left (\cos \left (d x + c\right ) + 1\right ) - 15 \, \log \left (\cos \left (d x + c\right ) - 1\right )\right )}}{240 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.40, size = 412, normalized size = 1.42 \begin {gather*} -\frac {360 \, a b^{2} \cos \left (d x + c\right )^{7} + 184 \, {\left (2 \, a^{3} - 15 \, a b^{2}\right )} \cos \left (d x + c\right )^{5} - 280 \, {\left (2 \, a^{3} - 15 \, a b^{2}\right )} \cos \left (d x + c\right )^{3} + 75 \, {\left ({\left (9 \, a^{2} b - 4 \, b^{3}\right )} \cos \left (d x + c\right )^{4} + 9 \, a^{2} b - 4 \, b^{3} - 2 \, {\left (9 \, a^{2} b - 4 \, b^{3}\right )} \cos \left (d x + c\right )^{2}\right )} \log \left (\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) \sin \left (d x + c\right ) - 75 \, {\left ({\left (9 \, a^{2} b - 4 \, b^{3}\right )} \cos \left (d x + c\right )^{4} + 9 \, a^{2} b - 4 \, b^{3} - 2 \, {\left (9 \, a^{2} b - 4 \, b^{3}\right )} \cos \left (d x + c\right )^{2}\right )} \log \left (-\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) \sin \left (d x + c\right ) + 120 \, {\left (2 \, a^{3} - 15 \, a b^{2}\right )} \cos \left (d x + c\right ) + 10 \, {\left (8 \, b^{3} \cos \left (d x + c\right )^{7} + 12 \, {\left (2 \, a^{3} - 15 \, a b^{2}\right )} d x \cos \left (d x + c\right )^{4} - 8 \, {\left (9 \, a^{2} b - 4 \, b^{3}\right )} \cos \left (d x + c\right )^{5} - 24 \, {\left (2 \, a^{3} - 15 \, a b^{2}\right )} d x \cos \left (d x + c\right )^{2} + 25 \, {\left (9 \, a^{2} b - 4 \, b^{3}\right )} \cos \left (d x + c\right )^{3} + 12 \, {\left (2 \, a^{3} - 15 \, a b^{2}\right )} d x - 15 \, {\left (9 \, a^{2} b - 4 \, b^{3}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{240 \, {\left (d \cos \left (d x + c\right )^{4} - 2 \, d \cos \left (d x + c\right )^{2} + d\right )} \sin \left (d x + c\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \left (a + b \sin {\left (c + d x \right )}\right )^{3} \cot ^{6}{\left (c + d x \right )}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 9.47, size = 471, normalized size = 1.62 \begin {gather*} \frac {6 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 45 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 70 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 120 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 720 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 120 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 660 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 3240 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 480 \, {\left (2 \, a^{3} - 15 \, a b^{2}\right )} {\left (d x + c\right )} + 600 \, {\left (9 \, a^{2} b - 4 \, b^{3}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) \right |}\right ) - \frac {320 \, {\left (9 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 18 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} + 18 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 36 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 24 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 9 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 18 \, a^{2} b + 14 \, b^{3}\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right )}^{3}} - \frac {12330 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 5480 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 660 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 3240 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 720 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 120 \, b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 70 \, a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 120 \, a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 45 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 6 \, a^{3}}{\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5}}}{960 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 7.06, size = 507, normalized size = 1.74 \begin {gather*} \frac {a^3\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5}{160\,d}+\frac {{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}\,\left (12\,a\,b^2-22\,a^3\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,\left (4\,a\,b^2-\frac {26\,a^3}{15}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4\,\left (96\,a\,b^2-\frac {78\,a^3}{5}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8\,\left (320\,a\,b^2-\frac {191\,a^3}{3}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6\,\left (408\,a\,b^2-\frac {296\,a^3}{5}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3\,\left (\frac {39\,a^2\,b}{2}-4\,b^3\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^9\,\left (216\,a^2\,b-196\,b^3\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5\,\left (\frac {519\,a^2\,b}{2}-\frac {484\,b^3}{3}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7\,\left (\frac {909\,a^2\,b}{2}-268\,b^3\right )-\frac {a^3}{5}-\frac {3\,a^2\,b\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{2}}{d\,\left (32\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{11}+96\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^9+96\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7+32\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5\right )}+\frac {{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3\,\left (\frac {a\,b^2}{8}-\frac {7\,a^3}{96}\right )}{d}-\frac {{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,\left (\frac {3\,a^2\,b}{4}-\frac {b^3}{8}\right )}{d}+\frac {\ln \left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )\,\left (\frac {45\,a^2\,b}{8}-\frac {5\,b^3}{2}\right )}{d}-\frac {\ln \left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )-\mathrm {i}\right )\,\left (\frac {a\,b^2\,15{}\mathrm {i}}{2}-a^3\,1{}\mathrm {i}\right )}{d}-\frac {\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (\frac {27\,a\,b^2}{8}-\frac {11\,a^3}{16}\right )}{d}+\frac {3\,a^2\,b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4}{64\,d}-\frac {a\,\ln \left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )+1{}\mathrm {i}\right )\,\left (2\,a^2-15\,b^2\right )\,1{}\mathrm {i}}{2\,d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
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